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Re: PHP upgrade broke my code!

Posted by steveg1701 on 01/31/08 00:21

On Jan 30, 1:29 pm, "Paul Lautman" <paul.laut...@btinternet.com>
wrote:
> steveg1...@yahoo.com wrote:
> > Hi, I hope one of you gurus out there can help me. I have a web
> > application that had been running fine before I upgraded my server,
> > now it fails on the following snippet of code:
>
> > function NextOrder($OrderID) {
> > ConnectDatabase();
> > $MyQuery = "SELECT OrderID FROM `Orders` WHERE (OrderID > $OrderID)";
> > $request = mysql_query($MyQuery);
> > list($Answer) = mysql_fetch_row($request);
> > echo "DEBUG next is ""$Answer""";
> > return $Answer;
> > }
>
> > When this code is interpreted it outputs this:
>
> > DEBUG next is ""
>
> > Not surprisingly, I have a companion routine that looks essentially
> > the same except for the < operator replacing > and sort order
> > descending - it fails in the same way. if however, for the purpose of
> > testing I replace the < with a = then the code works as expected;
>
> > Did I find a bug in PHP/MySQL somewhere or am I doing something wrong
> > that I was getting away with before and now getting my hand slapped by
> > smarter software? ;-)
>
> > The environment that this worked under is
>
> > PHP 5.2.0
> > SuSE 10.2 x586 32 bit
> > MySQL 5.0.26-12
> > PHP5-MySQL 5.2.0-10
>
> > Environment it failed under
>
> > PHP 5.2.4
> > SuSE 10.3 x86 64 bit
> > MySQL 5.0.45-22 x86 64 bit
> > PHP5-MySQL 5.2.4-10 x86 64 bit
>
> > Thanks in advance for any light you can shed on this!
>
> Where/how does the value $OrderID get set?

It's passed to the routine as a parameter. if I echo $MyQuery to the
output and paste the resultant query to MySQL then it works as
expected.

 

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