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Re: why does 69.99*100=6998?

Posted by The Natural Philosopher on 02/01/08 16:12

The Natural Philosopher wrote:
>
> The question says it all.
>
> I have an input box, which I fill in with a price.
> IOt gets passed to the main form as a variable, then shoved into an SQL
> field vue a print '%d' statement where the argument is $sale_price*100.
>
> For some reaosn, this particular value goes to 6998.
>
> If I update hee database manually to 6999, it displays as 69.99.
>
> If I enter 69.999 it updates as 6999..not 69999
>
> I must be doing something really dumb here..

Its even weirder.

I put in some checks:

echo $sale_price gives me 69.99
Echo ($sale_price*100) gives me 6999

But printf ("%d",$sale_price*100);

gives me 6998!!!

WTF is going on?

 

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