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Re: [PHP] Job for SQL or PHP?

Posted by "Kristen G. Thorson" on 08/03/05 19:21

Try

INSERT INTO Orders (SELECT '678',Cust_ID,Item_No,No_ordered FROM
Last_Order WHERE Cust_ID = '678')



kgt




-k. wrote:

>Just for the sake of example let's say i keep track of all of a customers previous orders in a
>table like this:
>
>Last_Order
>------
>Cust_ID
>Item_No
>No_ordered
>
>When a customer places an order i put the order details in an a table like this:
>
>Orders
>-----------
>Order_ID
>Cust_ID
>Item_No
>No_ordered
>
>
>Let's say when my customer returns he decides he wants everything he ordered previously plus some
>other stuff. Assuming this customer has unique customer ID of 345 and his current new order id is
>678. Can i copy his last order into the orders table with just a SQL statement like:
>
>INSERT INTO Orders VALUES ('678',(SELECT * FROM Last_Order WHERE Cust_ID = '678'))
>
>What i want to do is grab all the data from Last_Order associated with cust_id 345 (or whatever)
>and insert it into the Orders table with a Order_ID in this case 678. Let me know if this isn’t
>clear. This SQL obviously doesn't work, however, my question is there a way to do this with SQL
>alone? Or do i need to grab all the records from the Last_Order table loop through the record set
>and insert each new row into Orders individually?
>
>
>
>-k.
>
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>
>

 

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