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Posted by David Robley on 09/14/05 09:44
Florian Paucke wrote:
> Hi.
>
> I'm new to PHP.
>
> I need some help from you, because, I'm creating a
> guestbook. But I have a little problem.
>
> I have a table, where the different My-SQL-Entries
> are read out.
> But now I get only one Entry, but not more.
>
> How can do it, that the table read out 4 times, when
> 4 entries are in the database?
>
> And the cursor from the database are jumping to
> the next entry.
>
> Sorry for my bad english. :)
Assuming you are using a SELECT statement that returns more than one row,
you need to loop through the rows that are returned by your query. Have a
look at the examples for mysql_fetch_array in the php docs at
php.net/mysql_fetch_array The examples show the entire process from the
SELECT statement through to printing the results with printf.
You may find printf a bit daunting; echo might be easier for a beginner
unless you are used to C. To use echo, in example 3 replace
printf("ID: %s Name: %s", $row["id"], $row["name"]);
with
echo "ID: {$row["id"]} Name: {$row["name"]}";
Cheers
--
David Robley
I Never Knew A Cat Who Suffered From Insomnia.
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