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Posted by Kevin on 03/07/05 06:03
Greetings Mr Mattias,
I wish it was so simple. Because the dates that may need calculating can be
before 1970.
THis function I have.. and it's semi-working, but I've noticed
irregularities during the conversion.
Thanks for your suggestion!!
Yours,
Kevin
"Mattias Thorslund" <mattias@inreach.com> wrote in message
news:422BCBDA.1090309@inreach.com...
> M. Sokolewicz wrote:
>
> > well, you can simply use the unix timestamp, since the amount of days
> > / seconds since 0 AD/BC will be a constant (it won't change, trust
> > me), you can simply add it to that, and add a wrapper function to
> > php's time(). You'll be working with VERY big numbers in that case, so
> > you can also do it the other way around; store the amount of DAYS
> > since 0 AD/BC till Jan 1st 1970, add time()/86400, and you'll have the
> > amount of days since 0 AD/BC in an integer (or float, depending on how
> > many days that really are).
> >
> > You'll just need to find that constant somewhere :)
> >
>
> Can't be too hard to calculate it:
>
> 1970 * 365 + 1 day for each leap year. Note the rules for leap year, of
> course.
>
> /Mattias
>
> --
> More views at http://www.thorslund.us
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