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Re: $i++ problem understanding

Posted by Hilarion on 11/26/08 11:29

>>> But much harder to accept is and I fail to see the logic in it,
>>> is the following :
>>> $i = 1;
>>> print($i++);
>>> This will print 1 and only afterward will the value of $i be increased
>>> by 1. It is between (), so logic tells me first $i++ and then print.
>>> [snip]
>>
>> print is a language construct, not actually a function. That means that
>> the parentheses are optional.
>> [snip]
>
> My two cents:
> Post-increment operator does incrementation after the whole instruction
> (which contains it) is executed, not after the expression containing it
> is executed, so it does not matter if you are using some language construct
> like "print" or "echo" or some function or expressions with different
> operator priority and parentheses.
>
> Example:
>
> some_function(($i++ * 2) + 4) | 7);
>
> is equivalent to:
>
> some_function(($i * 2) + 4) | 7); $i += 1;
>
>
> Example for pre-increment operator:
>
> some_function((++$i * 2) + 4) | 7);
>
> is equivalent to:
>
> $i += 1; some_function(($i * 2) + 4) | 7);


I was wrong when I was writing it. If you are reading this post (possibly
in some newsgroup archives), then read the post by Chung Leong in this thread.
He described the operator correctly.


Hilarion

 

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