|
|
Posted by Ethilien on 10/13/05 01:46
Are you trying to put each return from array_slice into $output as an
array? You need to replace $output = array_slice... with $output[] =
array_slice...
Also, you cannot just echo an array (even of characters). It must be a
string, or else echo will only produce the output 'Array'.
Hope this helps,
-Connor McKay
Rodney Green wrote:
> Hello,
>
> I'm using a for loop to iterate through an array and slice parts of
> the array and add into another array.
>
> When array_slice is called the variable $i is not being substituted
> with the current value of
> $i and the $output array is empty after running the script. Can
> someone look at the code below and give me a clue as to why this
> substitution is not happening? If I uncomment the "echo $i;" statement
> the value of $i is printed just fine.
>
> Thanks,
> Rod
>
> Here's my code:
>
>
> $number = count ($int_range[start]);
> //echo $number;
> for ($i = 0; $i <= $number; $i++) {
>
> //echo $i;
>
> $output = array_slice ($textArray, $int_range[start][$i],
> $int_range[end][$i]);
>
> }
>
>
>
>
> foreach ($output as $value) {
>
> echo $value;
> }
Navigation:
[Reply to this message]
|