Posted by Scott Noyes on 10/24/05 20:42

> $query = "SELECT COUNT (login) FROM formacao WHERE login = '$login'";
> $result = mysql_query($query);

Make this line instead
$result = mysql_query($query) or die(mysql_error() . " with the query $query";
and you'll likely see the error.

--
Scott Noyes
snoyes@gmail.com

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