Posted by John Taylor-Johnston on 06/20/08 11:05

Hi,
I would like some help to improve this script. I'm a teacher with a schedule of 17 weeks.
Instead of using if(date("Y-m-d") >= $week3) I would like to do a "for i = 1 to 17" and if the current date date("Y-m-d") = week[i] I would like to echo "This is week $week[i]";

Can someone show me how please?


<?php
#old code:
$week1 = "2005-01-17";
$week2 = "2005-01-24";
....
$week17 = "2005-05-09;

if(date("Y-m-d") >= $week3)
{
echo "this is week 3");
}
?>

Thanks,
John

--
John Taylor-Johnston
-----------------------------------------------------------------------------
"If it's not Open Source, it's Murphy's Law."

''' Collège de Sherbrooke:
ô¿ô http://www.collegesherbrooke.qc.ca/languesmodernes/
- 819-569-2064

°v° Bibliography of Comparative Studies in Canadian, Québec and Foreign Literatures
/(_)\ Université de Sherbrooke
^ ^ http://compcanlit.ca/ T: 819.569.2064

• Next in thread: Re: [PHP] if(date("Y-m-d") >
• Next in forum: Re: [PHP] How do I start at a specific position in an array? Is there
• Prev in forum: Re: [PHP] Global class instances mysteriously set to NULL
• Thread view: if(date("Y-m-d") >

[Reply to this message]