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Posted by Adrian Bruce on 11/10/05 12:51
if (($_POST['$table_name']) == 1){
//do something
}
what you have is essentialll looking for a posted value called '$table_name== 1'!
Ross wrote:
>Thanks fpr all the feedback on the password but I have another one...
>
>How do I use $_POST with variables. Cant find an example of this anywhere on
>php.net
>
>
>if ($_POST['$table_name== 1']) {
>
>//do something
>
>}
>
>Ta,
>
>ross
>
>
>
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