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Posted by "Richard Lynch" on 11/22/05 23:36
Put all your footer html/code into a function called 'foot'
Then do:
if (must_die(...)){
foot();
exit;
}
On Tue, November 22, 2005 11:27 am, Bing Du wrote:
> Hi,
>
> One webpage has its banner, left menu and footer ect that are
> controled
> by the template. I want this php script to output the form and
> processing result within the page structure. Without exit, if the
> 'yourname' field is empty, the script would output 'Please enter your
> name!' fine within the page structure (that is, banner, menu and
> footer
> are all there). But obviously the script does not terminate as it's
> supposed to. With exit, the script terminates fine, but it outputs
> the
> result in a page without banner, menu and footer. So what's the
> correct
> way to get the script stop and output its results always in the page
> structure.
>
> <form method=post>
> <input name="yourname" type="text" size="20">
> <input name="submit" type="submit" value="submit">
> </form>
>
> <?php
>
> $submit = $_POST['submit'];
> $name = $_POST['yourname'];
>
> if ($submit)
> {
> if ($name=="")
> {
> print "Please enter your name!";
> //exit;
> }
> }
>
> echo "Continue processing...";
> ?>
>
> Thanks in advance,
>
> Bing
>
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