Posted by John Nichel on 03/24/05 21:03

Jay Blanchard wrote:
<snip>
> SELECT p.users
> FROM php.list p LEFT OUTER JOIN mysql.list m
> ON (p.phpuserid = m.mysqluserid)
> GROUP BY p.users
> HAVING clue > 0;
</snip>

I got zero results returned. ;)

--
John C. Nichel
ÜberGeek
KegWorks.com
716.856.9675
john@kegworks.com

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