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Posted by David Christensen on 03/24/05 21:24
Your example doesn't produce the desired the results!
The reason I posted to the PHP list was I thought I would have to apply
some ARRAY functions to produce the output I'm looking for. Your
example did nothing more than mine produced.
On Thu, 2005-03-24 at 12:48 -0600, Jay Blanchard wrote:
> [snip]
> I'm trying to figure out the best way to handle a SELECT from multiple
> tables where a single ID in tableA relates to multiple ID's in tableB:
>
> "SELECT tableA.ID, tableB.data FROM tableA, tableB WHERE tableA.ID=3 AND
> tableA.ID=tableB.tableAID"
>
> What I'm trying to product is an array output similar to:
>
> | ID | data |
> | 3 | data1, data2, data3 |
> [/snip]
>
> SELECT a.foo, b.foobar
> FROM tableA a LEFT OUTER JOIN tableB b
> ON(a.id = b.id)
>
> SELECT p.users
> FROM php.list p LEFT OUTER JOIN mysql.list m
> ON (p.phpuserid = m.mysqluserid)
> GROUP BY p.users
> HAVING clue > 0;
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