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Re: [PHP] Warning: mysql_fetch_row(): supplied argument is not a valid MySQL result resource

Posted by Drewcore on 10/08/32 11:14

just put a @ symbol before the function calll, eg

while ($myrow = @mysql_fetch_row($result)) {
etc


On 4/25/05, Mark Sargent <powderkeg@snow.email.ne.jp> wrote:
> Hi All,
>
> get the following error when calling data from mysql,
>
> *Warning*: mysql_fetch_row(): supplied argument is not a valid MySQL
> result resource in */var/www/html/phpmysqltable.php* on line *36
> *
> Below are snippets of my code,
>
> Line 22: $result = mysql_query("SELECT product_name,
> product_model_number, product_serial_number FROM Products",$db);
> Line 36: while ($myrow = mysql_fetch_row($result)) {
> printf("<tr><td>%s %s</td><td>%s</td><td>%s
> %</td></tr>\n",
> $myrow[1], $myrow[2], $myrow[3]);
>
> I'm following a webmonkey.com tut for php/mysql.
> http://webmonkey.wired.com/webmonkey/99/21/index3a.html
> Cheers.
>
> Mark Sargent.
>
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>
>


--
dc .. drewcore.com

 

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