|
|
Posted by Vedanta Barooah on 04/28/05 09:53
Hello All,
Cosider this :
function add($a=1,$b=2,$c=3){
return $a + $b + $c;
}
how do i skip the second argument while calling the function, is there
a process like this:
echo add(1,,1); # where i expect 2 to be printed,
how do i xcheive this.... m totally lost ! :((
Thanks,
Vedanta
Navigation:
[Reply to this message]
|