Posted by Vedanta Barooah on 04/28/05 09:53

Hello All,
Cosider this :

function add($a=1,$b=2,$c=3){
return $a + $b + $c;
}

how do i skip the second argument while calling the function, is there
a process like this:

echo add(1,,1); # where i expect 2 to be printed,

how do i xcheive this.... m totally lost ! :((
Thanks,
Vedanta

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