Posted by Peter van Schie on 11/24/88 11:27

wgerry wrote:

> //$query = 'SELECT * FROM `arrow` WHERE `Surname`LIKE \"%trimmed%\" ;

Should be something like:

$query = 'SELECT * FROM arrow WHERE Surname LIKE "%' . $trimmed . '%"';

> $results= mysql_query($query);
> $numrows= mysql_numrows($results);

Should be:

$numrows = mysql_num_rows($results);

HTH.

Peter.


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