Posted by rickcasey on 11/02/05 01:10

I cannnot seem to get exec() or passthru() to execute a perl script;
here's the code snippet:

if ($debug) {
echo "username1 = ".$username1."<br>";
echo "dbname = ".$dbname."<br>";
echo "SESSION[dbname] = ".$_SESSION['dbname']."<br>";
echo "Output file = ".$outputfile."<br>";
echo "Project name = ".$projectname."<br>";
echo "Study name = ".$studyname."<br>";
echo "The command to be run is: ".$cmd."<br>";
}

// Run the command!
exec($cmd,$myoutput,$rtnvar);
echo "rtnvar = ".$rtnvar."<br>";

foreach ($myoutput as $line) {
echo $line."<br>";
}

Which produces the results:

username1 = rick
dbname = cgb_lab_data
SESSION[dbname] = cgb_lab_data
Output file = myoutput
Project name = IBS11_1103
Study name = IBS 11
The command to be run is: perl
/home/caseyr/projects/LIMSScripts/3100DataIO/mk3100plt.pl -n 'IBS 11'
-b 1103 -o myoutput -p IBS11_1103 -i S
rtnvar = 13


The command looks perfectly legit, and will run at the command line if
I cut and paste it.

I do not understand the return value of 13.

I can get a simple perl script that takes no arguments to run ok; so I
think this has something to do with the arguments. I've used
escapeshellarg() to no avail. I've always tried the same with system()
and the backtick operator -- nada!

If anyone can spot what I might be doing wrong, I'd appreciate it!

Rick

• Next in forum: Re: how to use the PHP path to send something explicitly to the PHP parser?
• Prev in forum: how to use the PHP path to send something explicitly to the PHP parser?
• Thread view: cannot get exec() or passthru() to work?

[Reply to this message]