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Posted by Matthew Weier O'Phinney on 05/09/05 06:05
* Richard Collyer <richard@firebadger.net> :
> Ryan A wrote:
> > On 5/8/2005 5:33:46 PM, Richard Collyer (richard@firebadger.net) wrote:
> > > Ryan A wrote:
> > > > Sorry I know this is OT but I'm hoping someone will still
> > > > help...it should be quite simple :-)
> > > > I have a field in the database called "age" which is a DATE field.
> > > > I also have a webform where the user can select between which
> > > > ages he wants the records shown...
> > > > eg: if he types 23,25 then I should get all results where
> > > > age > =23 and age <=25
> > >
> > > What are you wanting? An sql query or a form?
> >
> > Thanks for replying.
> >
> > I have the form without a problem, I dont know how to format the SQL
> > query...
> > the birthdates in the DB are like this:
> >
> > 12-01-1979
> > 05-03-7955
> > etc
>
> Your looking at something like. For ages between 21 and 23
>
> $Upper = date("m-d-Y", mktime(0,0,0,date("m"),date("d"),date("y")-22));
> $Lower = date("m-d-Y", mktime(0,0,0,date("m"),date("d"),date("y")-23));
Easier than mktime() is strtotime:
$upper = date("m-d-Y", strtotime("-22 years"));
$lower = date("m-d-Y", strtotime("-23 years"));
However... since the OP will be using this in MySQL, use "Y-m-d" as the
date format (see the MySQL manual for valid date formats for comparisons).
--
Matthew Weier O'Phinney | WEBSITES:
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