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Posted by Oli Filth on 12/28/05 18:06
David Haynes said the following on 28/12/2005 15:44:
> Oli Filth wrote:
>
>> David Haynes said the following on 28/12/2005 14:42:
>>
>>> Oli Filth wrote:
>>>
>>>> black francis said the following on 28/12/2005 14:37:
>>>>
>>>>> try:
>>>>>
>>>>> $do = ($test == 1) ? true : false;
>>>>
>>>> Well, that can be shortened to:
>>>>
>>>> $do = ($test == 1);
>>>>
>>> Which can be shortened to:
>>>
>>> $do = $test;
>>>
>>> unless $test = 0, $do will evaluate as false.
>>>
>>
>> Technically, it's not the same. In the first two examples, $do will
>> *always* be a boolean. But in your new version, $do could be anything,
>> dependent on what type $test is.
>>
>>
> I disagree. My version simply relies on the casting rules for int to
> boolean. The example where ($test == 1) implicitly says that $test is of
> type integer not boolean since we know it would be $do = ($test == true)
> if $test was boolean.
>
I'm not sure what you're disagreeing with.
$do = ($test == 1) ? true : false;
and
$do = ($test == 1);
are exactly equivalent in every respect.
Whereas:
$do = $test;
not only results in $do being an integer (or whatever type $test is),
but when evaluated as a boolean (e.g. if ($do) {...}), does not result
in the same success/failure conditions. In fact, all you're doing is
copying the value, so this version achieves nothing!
--
Oli
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