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Posted by Kristen G. Thorson on 05/11/05 17:52
I don't understand what you're trying to do. Do you want two separate
list boxes, one for product types and one for makers? If so, use two
queries. Use the same block of code you have for product types to
populate the makers box. If that's not what you're looking for, you
need to describe what your goal is. You might also give more of your
table structure since you're asking about joins.
kgt
Mark Sargent wrote:
> Hi All,
>
> with wanting to show both product types(Switch, Router etc) and
> Makers(Cisco, Avaya, etc) on the one page in select boxes, I was
> wondering, do you use 2 seperate queries to the database or do you
> inner join to get all in 1..? I have set up different tables with
> related id's etc. So, to get Products.product_name and
> Products.product_id along with what the below query pulls, what wold
> be best..? I believe if I do a 2nd query, than some variables need to
> be identified with the particular query, yes..? Cheers.
>
> <html>
> <body>
> <hr>
> <h1 align=center>JUMBO STATUS</h1><p>
> <center>Used Hardware Specialist</center>
> <hr>
> <h2 align=center>Admin</h2>
> <table align="center" border="2">
> <tr>
> <td><h3 align=center>PRODUCT TYPE</h3></td>
> </tr>
> <tr><td><center>
> <select name="poduct_type">
> <?php
> $db = mysql_connect("localhost", "root", "grunger");
> mysql_select_db("status",$db);
> $result = mysql_query("SELECT ProductTypes.product_type_detail,
> ProductTypes.product_type_id FROM ProductTypes",$db);
> $num = mysql_num_rows($result);
> for ($i=0; $i<$num; $i++){
> $myrow=mysql_fetch_array($result);
> $product_type=mysql_result($result,$i,"product_type_detail");
> $product_type_id=mysql_result($result,$i,"product_type_id");
> echo "<option value=\"$product_type_id\">$product_type</option><br>";
> }
> ?>
> </select>
> </center>
> </td></tr>
> </table>
> <p>
> <p>
> <p>
> <hr><center>email: status1@zae.att.ne.jp<p>
> Telephone: 03-5209-1777<p>
> Fax: 03-5209-2539
> </center>
> <hr>
> </body>
> </html>
>
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