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Posted by Robert Meyer on 05/12/05 23:21
Hello,
Using: PHP Version 5.0.3
I build the following function:
function Set4HTMLOut() {
$C = func_num_args();
for ($I = 0; $I < $C; $I++) {
$A = func_get_arg($I);
echo 'I['.$I.']('.strlen($A).'): '.$A.'<br />';
$A = htmlspecialchars($A);
echo 'I['.$I.']('.strlen($A).'): '.$A.'<br />';
}
}
And called it like this:
Set4HTMLOut(&$LName, &$LOrg, &$LWebSite, &$LPhones, &$LComments);
echo '<br />After call:<br />'.
'LName: '.$LName.'<br />'.
'LOrg: '.$LOrg.'<br />'.
'LWebSite: '.$LWebSite.'<br />'.
'LPhones: '.$LPhones.'<br />'.
'LComments: '.$LComments.'<br />';
The "echo" statements in the Set4HTMLOut() function echos all the correct
data and proves the data was received correctly then altered by the
htmlspecialchars() function appropriately. Notice that the caller passes
each variable as a reference. Yet, the "echo" statement after the call
displays the data without any changes, like the first "echo" statement in
the Set$HTMLOut() function does.
Is it not possible to pass variables by reference to a variable-length
parameter list? Or am I doing something wrong? If so, what?
I have already built a work around. I do not need any work arounds. I just
think one should be able to pass variables by reference to a function that
accepts a variable-length parameter list.
Regards
Robert
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