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Posted by Jasen Betts on 02/19/06 06:03
On 2006-02-18, Bruce <bvanderweb@gmail.com> wrote:
> Consider the following code:
>
> $BB = -2181087916;
> $AA = (int)$BB;
> $AA = intval($BB);
>
> On some systems, $AA will be int(-2147483648), which is actually
> consistent with the documentation.
>
> On most systems, however, $AA will be int(2113879380), which is the
> same value truncated at 32 bits.
>
> I actually need the latter behavior, as it needs to duplicate Delphi
> code, which, like C, behaves the same way.
>
> This is encryption code that does a bunch of calculations on signed
> 32-bit numbers and ignores any overflows.
>
> Any ideas how I can do this?
after that do this.
$AA= (( $AA + 2147483648 ) & 4294967295) - 2147483648 ;
it should give the result you want on 64-bit machines
and be harmless on 32-bit machines.
Bye.
Jasen
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