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Posted by Stefan Rybacki on 10/18/05 22:23
Ian Davies wrote:
> Hello
> Im having problems displaying my images as thumbnails in a table. My code
> for producing the new width and height from the original image is as follows
> **************************************************
> if ($ImagePath) {
> //$Image = WEB_ROOT . 'images/PupilTester/' . $ImagePath;
> $Image = 'images/PupilTester/' . $ImagePath;
> } else {
> $Image ='images/PupilTester/nopicture.bmp';
> }
>
> $size = getimagesize($image);
> $height = $size[1];
> $width = $size[0];
> if ($height > 150)
> {
> $height = 150;
> $percent = ($size[1] / $height);
> $width = ($size[0] / $percent);
> }
> else if ($width > 150)
> {
> $width = 150;
> $percent = ($size[0] / $width);
> $height = ($size[1] / $percent);
> }
> //echo "<img src\"image/path/image.jpg\" height=\"$height\"
> width=\"$width\" />";
> **************************************************************
>
> and in my table to display the thumbnail I have
>
> **************************************************************
> <td rowspan="5" valign="top"><div align="left"><img src=<?php echo $Image;
> ?> width= <?php echo "$width"?> height= <?php echo "$height"?>>
> </div></td>
> </tr>
> ****************************************************************
> However the images are not showing at all. The cells of the table are blank.
> But if I use
>
> *********************************************
> <td><img src=<?php echo $Image; ?>></td>
> </tr>
> *******************************************
> The images show full size as normal. Can anyone see where Ive gone wrong
>
Wrong approach.
Use a separate script for showing the images
<img src="showthumbnail.php?img=xxxxxx">
Regards
Stefan
> Thaks
> Ian
>
>
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