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Re: [PHP] imagejpeg() output

Posted by Greg Donald on 01/17/05 04:10

On Sat, 15 Jan 2005 08:39:16 -0800, Steven Simmons <low@lowbatteries.com> wrote:
> I'm trying to write an object oriented system for saving my uploaded
> files to a blog.
>
> I am using php to resize the original photos and save a thumbnail .
>
> When I get all done, I want to do something like this:
>
> $tempImageData = imagejpeg( $imageResource, '', 75 );
> $outputHandler -> save ( $tempImageData );
>
> Where the $outputHandler is an object that knows how/where to save the file.
> However, I've noticed that imagejpeg() only returns a number 1.
>
> This worked on my previous server, but I'm guessing my new server has a
> newer version of php.
>
> What am I doing wrong? How can i pass the raw jpeg data to a function?

To resize the image you have to create a new image handler to write
the new jpeg data to. You can create that image handler with
imagecreatetruecolor() for example.

imagejpeg() is for outputting the data to the browser.


--
Greg Donald
Zend Certified Engineer
http://destiney.com/

 

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