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Posted by David Graham on 11/23/31 11:41
"David Dorward" <dorward@yahoo.com> wrote in message
news:dubq4k$f33$1$830fa7a5@news.demon.co.uk...
> David Graham wrote:
>
> > "The 50% 0 bit refers to the positioning of the background image
>
> > I thought this would move the image over 50% from the left edge,
resulting
> > in no image being present down the left half of the screen.
>
> No. It puts the point $x% along the image $x% along the horizontal length
of
> the container. So 100% would put the right hand edge of the image along
the
> right hand edge of the container. 10% would put the put 10% along the
image
> 10% along the container. And so on.
>
Thanks for that
So, 0% would put the left edge of the image on the left side of the
container. No need to confirm I'm sure that is correct from what you say.
bye
David
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