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Posted by ColdShine on 10/04/96 11:42
Anonymous in news:4416CEBE.92F38532@nowhere.invalid wrote:
> ColdShine wrote:
>
>> Here's a quick roundup, if you (or anyone f'wing this thread) still are
>> wondering WHAT is meant WHEN:
>>
>> <?php
>> $arr = array('key' => 'foo');
>> define('key', 'another');
>>
>> echo $arr[key]; // undefined index ('another')
>> echo $arr['key']; // foo
>> echo '$arr[key]'; // $arr[key]
>
> Ok, these results are obvious, IMHO.
I included those for the sake of completeness...
>> echo "$arr[key]"; // foo
>> echo "$arr['key']"; // parse error
>
> But these two are not. For the first case: Where in the manual does it
> state that "$arr[key]" should be evaluated like $arr["key"]? For the
> second: Within double quotes variables should be evaluated, so why
> doesn't $arr['key'] evaluate to foo?
This answers your questions:
http://www.php.net/manual/en/language.types.string.php#AEN3054
If you could not find this in the manual it's your fault, as it's just
where... you should expect it to be :)
>> This should rule out any misunderstandings.
>
> Yes, it did. But it also brought up two new questions on my part. :-)
....and anyone else's who's not read the manual of course.
--
ColdShine
"Experience is a hard teacher: she gives the test first, the lesson
afterwards." - Vernon Sanders law
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