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Posted by JHollis on 01/06/05 07:34
nevermind...i figured it out. I will read up on sessions and test some
things with what you posted and if i have anymore questions, i will post
them. Thanks Jerry.
If anyone else has any other suggestions, please feel free to share them
with me.
JHollis wrote:
> Where do i need to start my session? Ive copied and pasted exactly what
> you have typed..and the form doesnt display unless i hard code the
> variable to "NO".
>
> Jerry Kita wrote:
>
>> I do exactly the same thing on my website. I use PHP's Session
>> handling to determine if a user is actually logged on.
>>
>> You can see that I check a variable called $validlogon which I set to
>> either YES or NO at the beginning of the script
>>
>> <?php
>> if ($validlogon == "NO") {
>> print "<p class=\"hnavbar\">Salkehatchie Members Login Here:<br>\n";
>> print "<form action=\"Salkehatchie_LoginScript.php\" method=\"POST\">\n";
>> print "<p class=\"login\"><small>USER ID:</small><br>\n";
>> print "<input type=\"text\" name=\"userid\"><br><br>\n";
>> print "<small>PASSWORD:</small><br>\n";
>> print "<input type=\"password\" name=\"password\"><br><br>\n";
>> print "<input type=\"submit\" value=\"Enter\"></p>\n";
>> print "</form>\n";
>> }
>> ?>
>>
>> Near the beginning of my script I check for the existence of a valid
>> session
>>
>> <?php
>> if (isset($_SESSION[userid])) {
>> $validlogon = "YES";
>> } else {
>> $validlogon = "NO";
>> }
>> ?>
>>
>> Setting the $validlogon variable allows me to do a number of useful
>> things. For example, there are certain parts of the webpage that I
>> reveal to logged in users. Checking $validlogon allows me to decide
>> dynamically what to render to the browser. In the following I display
>> a message showing the user as being logged in and give them a link that
>> logs them out.
>>
>> if ($validlogon == "YES") {
>> print "<table style=\"width: 100%\";>\n";
>> print "<tbody>\n";
>> print "<tr>\n";
>> print "<td width=\"50%\"><p class=\"login\"><small><b>YOU ARE
>> LOGGED IN AS: $_SESSION[userid]</b></small></p></td>\n";
>> print "<td width=\"50%\"><p class=\"login\"><small><b>CLICK <a
>> href=\"LogoutScript.php\"> here</a> TO LOGOUT</b></small></p></td>\n";
>> print "</tr>\n";
>> print "</table>\n";
>> }
>>
>> Hope this is helpful
>>
>> Jerry Kita
>>
>> JHollis wrote:
>>
>>> I had this code working the way i wanted it to (as far as correct
>>> username and password allowing successful login)...but what i want to
>>> happen now is when a user successfully logs it it will make the login
>>> form disappear and just say successfully logged in or welcome user
>>> and a link below it so they can log off and make the form re-appear.
>>> Below is the code that i have where i tried to get it to disappear on
>>> successful login, but it stays disappeared all the time. Can someone
>>> please point out what im doing wrong. I have tried everything i can
>>> think of...and nothing works. Im a PHP newbie...so im sure some of
>>> you might get a laugh out of this...if it is real easy.
>>>
>>> <---snippet
>>>
>>>
>>> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN"
>>> "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd">
>>> <html>
>>> <head>
>>> <link href="style.css" rel="stylesheet" type="text/css" />
>>> </head>
>>> <body>
>>> <div id="container">
>>> <div id="top">
>>> <h1>header</h1>
>>>
>>> </div>
>>> <div id="leftnav">
>>> <p>
>>>
>>> <?php
>>>
>>> $username=$_POST['username'];
>>> $password=$_POST['password'];
>>> $db="user";
>>> $server="localhost";
>>> $db_username="root";
>>> $db_password="*******";
>>> $connect = mysql_connect($server,$db_username,$db_password);
>>> if (!$connect) {
>>> die ("could not connect to database");
>>> }
>>> $select = mysql_select_db($db,$connect);
>>> if (!$select) {
>>> die ("could not select database $db");
>>> }
>>> /*username='$username'";*/
>>> $sql = "SELECT * FROM passwords, user_info where id=PID and
>>> username='$username'";
>>> $result = mysql_query($sql);
>>> /*$num_rows = mysql_num_rows($result);*/
>>> while ($user = mysql_fetch_array($result))
>>> {
>>> $id = $user['id'];
>>> $username2 = $user['username'];
>>> $password2 = $user['password'];
>>> $firstname = $user['firstname'];
>>> $email = $user['email_address'];
>>> IF ($username=="$username2" &&
>>> $password=="$password2")
>>> {
>>> echo("\"Welcome, <b>$firstname</b>\"");?><br><?
>>> echo ("\"Your email address is <b>$email<b>\"");?></td><tr>
>>> <a
>>> href="<?$_SERVER['PHP_SELF']?>?username=""&?password=""">Logoff</a><?
>>> break;
>>> }
>>> else
>>> {
>>> ?>
>>> <FORM action="<?$_SERVER['PHP_SELF']?>" method="post">
>>> <INPUT type="hidden" name="id">
>>> <table>
>>> <td><b>*</b>Username:</td> <td><INPUT class="input"
>>> size="8" type="text" name="username" value="<?echo
>>> $username?>"></td><tr>
>>> <td><b>*</b>Password:</td> <td><INPUT class="input"
>>> size="8" type="password" name="password"></td><tr>
>>> <td class="xsmall"><b>* Case Sensitive</b></td>
>>> <td><INPUT type="submit" value="Login"></td><tr>
>>> <td>  </td>
>>> </table>
>>> </FORM>
>>> <?
>>> break;
>>> }
>>> } //IF ($username != $username2 || $password !=
>>> $password2) {//
>>>
>>> ?><br>
>>> <?
>>> if ($username == "" && $password == "") {
>>> echo ("Please type in a Username and Password");}
>>>
>>> if ($username != "" && $password == "") {
>>> echo ("Please type in a password");}
>>>
>>> if ($username == "" && $password != "") {
>>> echo ("Please type in a username and password");}
>>> ?>
>>> </p>
>>> </div>
>>> <?if (($username2==$username && $password2==$password) &&
>>> ($username2!="" || $password2!="")){?>
>>> <div id="rightnav" class="box">
>>> <p>
>>> </p>
>>> </div>
>>> <?}?>
>>> <div id="content">
>>> <h2>Subheading</h2>
>>> <p>
>>> </p>
>>> <p>
>>> </p>
>>> </div>
>>> <div id="footer">
>>> <p>
>>> Today is
>>> <?php
>>> echo( date("F dS Y."));
>>> ?>
>>> </p>
>>> </div>
>>> </div>
>>> </body>
>>> </html>
>>> ---->snippet
>>
>>
>>
>>
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