Posted by webramz on 04/04/06 11:48

Write your code like this:

$query = "....";
$result = mysql_query($query);
if($result) {
$num_rows = mysql_num_rows($result); // notice the Result Resource
here //
} else {
echo mysql_error();
// die();
}


Best Regards,

• Next in forum: Javascript
• Prev in forum: Re: gd and loss of quality
• Thread view: Re: mysql_num_rows HELP

[Reply to this message]