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 Posted by robert on 06/13/43 11:45 
| The solution is: 
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| select grad_pbroj, Naziv, COUNT(*) as brojac from smjestaj left join grad  
on 
| grad.grad=smjestaj.grad_pbroj group by grad_pbroj order by grad_pbroj ASC 
 
 
i don't think so...that should cough up a nasty error as "naziv" is not  
handled in the group by clause nor is it part of an aggrigate function...and  
that's just me eye-balling it for .5 seconds. 
 
btw...people who DONT format their inline sql should be shot! which is more  
manageable, the above or: 
 
SELECT     s.grad_pbroj               , 
           s.Naziv                    , 
           COUNT(*)       brojac 
FROM       smjestaj       s 
LEFT JOIN  grad           g ON 
           g.grad         = s.grad_pbroj 
GROUP BY   s.grad_pbroj   , 
           s.Naziv 
ORDER BY   s.grad_pbroj   ASC 
 
 
** and if this query is to return the number of duplicates, then there  
should either be a where or having clause that only returns a row if the  
count is > 1. 
 
but that's just me following real-world, professional standards. the former  
should just be all on one line for christ' sake.
 
  
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