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Posted by Markus.Baerlocher on 04/24/06 11:00
Dear css-Professionals,
thanks a lot for your advices! (and sorry for my switzerland-english)
In the last days I read (and understand) a lot about the advantages of
CSS.
It is easy to split content and style by calling style.css in <head>.
Unfortunately my .php doesn't have a "<head>"...
The story behind:
I use a BIG open-source-prog for genealogy.
I try to append it to a "small CMS" (for this I need the
"2-column-layout").
Of corse it will be VERY much better with css!
But in the .php which does my things, there is no <head> where I could
link-in the .css
Alternatively I tried this "table-working-around".
I now something about HTML, and now a little about CSS - but nothing
about PHP.
I use the given content.php, and customyse it after:
echo <<<TEXT
with some HTML-code.
This is bevore "echo <<<TEXT":
----------------------------------
<?php
//----- Globale Einstellungen ( wird für Anzeige benötigt!)
------//
require("config.php");
require("includes/functions_charts.php");
require($PGV_BASE_DIRECTORY.$factsfile["english"]);
if (file_exists($PGV_BASE_DIRECTORY . $factsfile[$LANGUAGE])) require
$PGV_BASE_DIRECTORY . $factsfile[$LANGUAGE];
// -- print html header information
print_header($name." ".$pgv_lang["descend_chart"]);
if (strlen($name)<30) $cellwidth="100%";
else $cellwidth=(strlen($name)*14);
print "\n\t<table class=\"list_table, $TEXT_DIRECTION\"><tr><td
width=\"${cellwidth}px\" valign=\"top\">\n\t\t";
// print "\n\t<h2>".$pgv_lang["descend_chart"].":<br
/>".PrintReady($name)."</h2>";
//----- HTML- content ----------------//
echo <<<TEXT
------------------------------------------
(which I desn't understand - but it works)
I put in this content.php my HTML, including all local style-formats.
For every new content, I repeate the whole PHP- and CSS-stuff around in
many content.php's.
Then I call the content.php's by a menu.php: $submenu["link"] =
"1th-content.php";
Of corse, the best way is to split:
- XHTML-content (a lot of pages)
- style.css
- display.php to call the content and the style
and in the menu.php I call the display.php with a parameter for the
specific content.html
But I have no idea HOW to do this...
Thanks a lot for your support!
Markus
if you will have a look:
http://www.lau-net.de/baerlocher/phpGedView/z_HTML-Test.php
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