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Posted by Alan Little on 05/18/06 14:20
Carved in mystic runes upon the very living rock, the last words of
Kimmo Laine of comp.lang.php make plain:
> "Alan Little" <alan@n-o-s-p-a-m-phorm.com> wrote in message
> news:Xns97C6A5C373D05alanphormcom@216.196.97.131...
>> Carved in mystic runes upon the very living rock, the last words of
>> Rik of comp.lang.php make plain:
>>
>>> Alan Little wrote:
>>>> Carved in mystic runes upon the very living rock, the last words of
>>>> Ambush Commander of comp.lang.php make plain:
>>>>
>>>>> It looks like in this particular case, $this->$x should be
>>>>> sufficient.
>>>>
>>>> Thanks, but no.
>>>>
>>>>> Otherwise, you may have to split up x into $x_object and $x_name
>>>>> (exploding by -> should be sufficient) and calling
>>>>> $x_object->$x_name. What you currently have, however, cannot be
>>>>> done.
>>>>
>>>> I'm not sure what you mean.
>>>> What I'm trying to do is parse variables
>>>> out of a string and substitute them with the value. $x (in this
>>>> example) would hold the variable name extracted from the string.
>>>> I'm trying to figure out how to get to the value of that variable,
>>>> from there.
>>>
>>> That is exactly what it does.
>>> $x = 'string'
>>>
>>> $$x = $this->$x;
>>> equals:
>>> $string = $this->string;
>>>
>>> $x is the variable name, $variable_name holds the value......
>>>
>>> I don't get the problem?
>>>
>>> What is the exact reason you're trying to accomplish? Maybe if you
>>> elaborate some more, we get the picture. Why is it this doesn't
>>> suffice?
>>
>> For example:
>>
>> $this->animal = 'lamb';
>> $this->string = 'Mary had a little {{animal}}';
>>
>> The goal is to extract 'animal' from the string (no problem), convert
>> it to 'lamb' and replace it in the string (again, no problem). The
>> question is, if I have 'animal', how do I get 'lamb'? In global
>> space, I would simply have 'animal' in a variable, and use $$var to
>> get 'lamb'.
>
> So again, wouldn't this work:
>
> $var = 'animal';
> $this->$var; //this is translated to $this->animal, which in turn
> gives you 'lamb' .
Yes, that works; I just didn't understand what AB was saying.
--
Alan Little
Phorm PHP Form Processor
http://www.phorm.com/
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