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Re: [PHP] Php error with MySql

Posted by John Nichel on 01/06/05 21:20

Wil Hitchman wrote:
> I get the following error
> Warning: mysql_num_rows(): supplied argument is not a valid MySQL result resource in /home/wilmail/public_html/elblog.php on line 7
> &n=& //error ends here
> with the following bit of code
> $qResult = mysql_query ("SELECT * FROM blog_entries ORDER BY id DESC");
> $nRows = mysql_num_rows($qResult);
> $rString ="&n=".$nRows;
> If I am just naming a variable how is the argument not valid?
> Thanks,
> Wil

Echo out mysql_error() after you execute mysql_query()

John C. Nichel



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