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Posted by Jerry Stuckle on 11/29/06 01:57
NC wrote:
> Thomas Mlynarczyk wrote:
>
>>>sam wrote:
>>>
>>>>What is the meaning of this operator:-
>>>>=>
>>>
>>>Assignment - used in arrays?
>>
>>Hm. But why the need for a special operator here? Wouldn't
>>a simple = have done the job just as well?
>
>
> Yes, but you'd have to write it differently.
>
> Consider this simple example:
>
> $someArray = array('field1' => 1, 'field2' => 'two');
>
> If it equivalent to:
>
> $someArray = array();
> $someArray['field1'] = 1;
> $someArray['field2'] = 'two';
>
> Moreover, the second option might trigger an E_NOTICE, since
> you would be trying to assign a value to a not-yet-defined member
> of the array...
>
> Cheers,
> NC
>
Actually, the second option is perfectly valid. It's fine to assign to
an array element which hasn't been defined yet. Just don't try to USE
an array element (or any other variable) before it's been defined.
--
==================
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Jerry Stuckle
JDS Computer Training Corp.
jstucklex@attglobal.net
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