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Re: Link parameter problem

Posted by shimmyshack on 03/21/07 16:45

On 21 Mar, 15:24, "Lennart Anderson" <lennart.ander...@tele2.se>
wrote:
> I want to present a table with main data. Each revord will have a field
> acting like a link to a new page with detailed data on the selected record.
> My problem is that I can't get the record-ID parsed into the link parameter.
> Whatever I do will just let my $_GET['id'] give me what is after the
> equal-sign in the link prameter.
> The code is:
> while($row = mysql_fetch_object($result))
> {
> $mid = ($row->catid);
> $name = ($row->catname);
> echo '<tr>';
> echo '<td >' . $mid . '</td>';
> echo '<td>' . '<a href="advertinfo.php?id=$mid">' . $name . '</a></td>';
> echo '</tr>';
> }
> echo '</table>';
>
> In this case the $_GET on advertinfor.php will only give me $mid.
> I think the problem might be in the quotes but I also think I have tested
> every possible combinaion without success.
> Any solution or hint is very much appreciated.

have you tested this combination?
$mid = 'test';
echo '<td><a href="advertinfo.php?id=' . $mid . '">' . $name . '</a></
td>';

 

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