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Posted by Lennart Anderson on 03/21/07 16:54
"shimmyshack" <matt.farey@gmail.com> skrev i meddelandet
news:1174495509.099426.305700@e65g2000hsc.googlegroups.com...
> On 21 Mar, 15:24, "Lennart Anderson" <lennart.ander...@tele2.se>
> wrote:
>> I want to present a table with main data. Each revord will have a field
>> acting like a link to a new page with detailed data on the selected
>> record.
>> My problem is that I can't get the record-ID parsed into the link
>> parameter.
>> Whatever I do will just let my $_GET['id'] give me what is after the
>> equal-sign in the link prameter.
>> The code is:
>> while($row = mysql_fetch_object($result))
>> {
>> $mid = ($row->catid);
>> $name = ($row->catname);
>> echo '<tr>';
>> echo '<td >' . $mid . '</td>';
>> echo '<td>' . '<a href="advertinfo.php?id=$mid">' . $name . '</a></td>';
>> echo '</tr>';
>> }
>> echo '</table>';
>>
>> In this case the $_GET on advertinfor.php will only give me $mid.
>> I think the problem might be in the quotes but I also think I have tested
>> every possible combinaion without success.
>> Any solution or hint is very much appreciated.
>
> have you tested this combination?
> $mid = 'test';
> echo '<td><a href="advertinfo.php?id=' . $mid . '">' . $name . '</a></
> td>';
>
EUREKA
I have tested your suggestion now and it work.
Don't know how to thank you.
Now I can keep some of the hair on mu head instead of rubbing it o0f in deep
frustration.
Again thanks for the hint
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