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Re: [PHP] date() problem

Posted by Edward Vermillion on 07/07/05 01:17

On Jul 6, 2005, at 4:44 PM, Philip Hallstrom wrote:

>> of leap years between the two dates. Leap years occur every 4 years,
>> and 17 / 4 = 4.25, so there were 4 leap years between 7/6/88 and
>> 7/6/05 and
>
> Just to nitpick... :-)
>
> http://en.wikipedia.org/wiki/Leap_year
>
> The Gregorian calendar adds an extra day to February, making it 29
> days long, in years where the quotient has no remainder when divided
> by 4, excluding years where the quotient has no remainder when divided
> by 100, but including years where the quotient has no remainder when
> divided by 400. So 1996, 2000, and 2400 are leap years but 1800, 1899,
> 1900 and 2100 are not.
>
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>
>

I always wondered what kind of drugs those guys were on when they came
up with the leap-year system... :P

One interesting side note to the op's problem, since I'm not going to
be able to do anything else till I figure this out now..., if one of
the dates is a leap year the 365.25 works fine, which make me wonder
how the strtotime() function is working... or maybe that's what it's
supposed to do... ;)

Edward Vermillion
evermillion@doggydoo.net

 

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