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Re: [PHP] date() problem

Posted by Edward Vermillion on 07/07/05 01:31

On Jul 6, 2005, at 5:17 PM, Edward Vermillion wrote:

>
> On Jul 6, 2005, at 4:44 PM, Philip Hallstrom wrote:
>
>>> of leap years between the two dates. Leap years occur every 4
>>> years, and 17 / 4 = 4.25, so there were 4 leap years between 7/6/88
>>> and 7/6/05 and
>>
>> Just to nitpick... :-)
>>
>> http://en.wikipedia.org/wiki/Leap_year
>>
>> The Gregorian calendar adds an extra day to February, making it 29
>> days long, in years where the quotient has no remainder when divided
>> by 4, excluding years where the quotient has no remainder when
>> divided by 100, but including years where the quotient has no
>> remainder when divided by 400. So 1996, 2000, and 2400 are leap years
>> but 1800, 1899, 1900 and 2100 are not.
>>
>> --
>> PHP General Mailing List (http://www.php.net/)
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>>
>>
>
> I always wondered what kind of drugs those guys were on when they came
> up with the leap-year system... :P
>
> One interesting side note to the op's problem, since I'm not going to
> be able to do anything else till I figure this out now..., if one of
> the dates is a leap year the 365.25 works fine, which make me wonder
> how the strtotime() function is working... or maybe that's what it's
> supposed to do... ;)

But then, even if I do figure this out, it's still going to tell me I'm
only 35... which is a bit off...

As usual Richard's way is probably the best for any "real world" age
deduction. ;)


Edward Vermillion
evermillion@doggydoo.net

 

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