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Posted by Shawn Wilson on 09/30/05 06:11
"Marc Bissonnette" <dragnet@internalysis.com> wrote in message
news:Xns96E0D447071Edragnetinternalysisc@216.196.97.131...
> "Shawn Wilson" <firstinitial_lastname@dvigroup.net> wrote in
> news:Eu%_e.13754$so3.8195@fe06.news.easynews.com:
>
>> This was almost asked recently, but not quite how I need to use it. I
>> tried to extrapolate, but alas I need some clarification.
>>
>> What I am doing is displaying an image in a photo album. I get to the
>> page in question with this:
>>
>> detail.php?picid=101
>>
>> That page then calls a function to find out what set that pic belongs
>> to, and then I need to know that pics position in the whole scheme of
>> things. i.e. this is pic 5 of 10.
>>
>> Up to this point, I have the picid and the setid it belongs to.
>>
>> Since the mySQL return is an array that I normally step through,
>> shouldn't I be able to skip stepping through it myself and simply
>> search the return from mySQL for what I'm looking for and pull out
>> it's position in the array without stepping through it?
>>
>> here's the long way (that works):
>>
>> -----
>> function get_pic_position($picid_sent,$setid) {
>> $query = " SELECT picid FROM `pic` WHERE `setid` = '$setid' ORDER BY
>> `sort`
>> ASC, `picid` ASC; ";
>> $result = mysql_query($query) or die('Query failed: $query<br><br>' .
>> mysql_error());
>> while ($line = mysql_fetch_array($result, MYSQL_ASSOC)) {
>> foreach($line AS $_NAME => $_VALUE) { $$_NAME = $_VALUE; }
>> $array_pic_ids[] = $picid;
>> # buidling this array is redundant isn't it?
>> }
>>
>> $array_pic_position = array_keys($array_pic_ids, $picid_sent);
>> # can't I do this search directly on the results somehow?
>>
>> $pic_position = $array_pic_position[0];
>> # is there a cleaner way of turning this one record array into a
>> non-array?
>>
>> return $pic_position;
>> }
>> -----
>>
>> But I'm just thinking that there has to be a shorter way to do that,
>> right?
>
> Hrm, lemme take a crack at it (this is perl, hope you don't mind)
>
> Here's the quick and dirty way, assuming that each picture is numbered
> sequentially, as they're entered, with no skipped numbers:
>
> $query = "SELECT count(*) FROM `pic` WHERE `setid` = '$setid'";
> my $dbh;
> my $sth;
> $dbh = DBI->connect("DBI:mysql:$dbname", $dbuser, $dbpass,{RaiseError=>
> 1});
> $sth=$dbh->prepare($query);
> $sth->execute();
> $totalresults=$sth->rows;
> $sth->finish;
> $dbh->disconnect;
> $picture_position= "Picture is $picid_sent of $totalresults pictures in
> set";
>
> If there are skipped positions:
>
> $query = "SELECT `picid` FROM `pic` WHERE `setid` = '$setid' ORDER BY
> `sort` ASC, `picid` ASC";
> my $dbh;
> my $sth;
> $dbh = DBI->connect("DBI:mysql:$dbname", $dbuser, $dbpass,{RaiseError=>
> 1});
> $sth=$dbh->prepare($query);
> $sth->execute();
> $totalresults=$sth->rows;
> $count = 1;
> while (@row=$sth->fetchrow()) {
> if ($row[0] == $picid_sent) {
> $pic_position = $count;
> }
> ++$count;
> }
> $sth->finish;
> $dbh->disconnect;
> --$count;
> $picture_position= "Picture is $pic_position of $count pictures in set";
>
> Does that help, or did I completely miss what you needed ?
>
>
> --
> Marc Bissonnette
> CGI / Database / Web Management Tools: http://www.internalysis.com
> Looking for a new ISP? http://www.canadianisp.com
No, you've got the idea, but you're stepping through it like I am. I was
thinking there had to be a way to use that $sth array (since that's what it
is, is an array of your whole result set) and step through that without
having to assign the data to another variable or array. In my case, that
result array is stored in $result... but the idea is the same. So far, my
attempts to step through that array have failed but I was thinking it was
because I'm doing something wrong.
Maybe I'm just being too picky, but if I can avoid making a new array by
using one that is already populated that would make more sense to me.
--
Shawn Wilson
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