Posted by Ian B on 11/18/05 14:59

Stefan,

With

$arr[1]

PHP can't know if you have an array, or if you want to output the value
of $arr followed by the literal string "[1]"

it assumes the former. If you want the latter, you have to use

"Array value = {$arr[1]}"

(i.e. put curly braces round it)

Ian

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