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Posted by Etienne Marais on 11/18/05 15:20
Stefan Mueller wrote:
>> $myarray[3][5] = "Text 1";
>> $myarray[3][6] = "Text 2";
>>
>> is perfectly valid.
>
> You are rigth, it's working. My problem was that the output command was
> wrong.
> I used
> echo "Output: $myarray[3][5]<p>";
> and this showed me
> Output: Array[5]
Consider print_r for structures, eg. print_r($myarray)
during development and debugging.
Etienne Marais
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