Date: 03/03/09 (Computer Geeks)    Keywords: programming, java, web

Hello, I'm looking for some help with a Java programming assignment.

The assignment is to create a program in which the user can enter the number of dice they wish to roll and a score. The program is supposed to calculate the probability of the score occurring when their dice have been rolled 100,000 times.

I am unsure of how to create multiple dice. We've been looking at programs in which you roll one or two dice and then do something with the outcome. How would I go about making it possible to add up the scores of many dice (the user's choice of # of dice, to be exact)? I've formed a primitive Scanner for this but don't know what to add.


This is all within the class "DiceTester". I have a class "SimpleDice" set up to randomly select a number 1-6 when a die is rolled.

     Scanner scanDie = new Scanner(System.in); // first scanner
 System.out.println("Enter number of dice");
 int n = scanDie.readInt(); // this is where user enters # of dice
  if (n < 0) // if user enters # less than 0
   System.out.println("Error: Number must be 0 or greater."); // there will be an error


    Scanner scanScore = new Scanner(System.in); // second scanner
    SimpleDice d = new SimpleDice();
 System.out.println("Enter score");
 int m = scanScore.readInt(); // this is where user enters score
 if (m < 0) // if user enters score less than 0
   System.out.println("Error: Score must be 0 or greater"); // there will be an error
    
    int tossCount = 100000; // this is the total # of tosses (designated by assignemnt)
    int scoreCt = m; // this is saying that the # the user entered (m) is now the score count
    int tossResult;
    
    for(int j = 0; j < tossCount; j++){ // for loop used to add up tosses
      tossResult = d.throwDice();
      
      if(tossResult == m) scoreCt++;}
    System.out.println("Success Rate: " + ((double)scoreCt)/tossCount); // this divides the #of times m occurred by the #of times the dice were rolled

Source: http://community.livejournal.com/computergeeks/1245562.html