Date: 11/08/06 (PHP Development)    Keywords: html, web

I'm attempting to grab a web cam image, which has its own server/URL, and display it on a page on our server.

This works:

print ("\n");

But I'd like to grab the file for later saving/manipulating, and also avoid having the auth amd IP info in the HTML source - so I tried:

$camimage = fopen("http://" . $user . ":" . $password . "@" . $ip . "/" . $filename, "rb");

and it times out with:

Warning: fopen(http://...@69.9.5.12:84/IMAGE.JPG) [function.fopen]: failed to open stream: Connection timed out on line 24.

Anyone have any clue why? Is it the username/password that's the problem? The explicit port number? (I can't get around needing the authentication, but I might be able to redo to use port 80)

Source: http://community.livejournal.com/php_dev/73616.html