Date: 03/21/07 (PHP Community)    Keywords: no keywords

I'm having a stupid day.

I have a class. That class has an array variable. I want to create an instance of another class into an object, cache it in the array and return a reference to that object.

e.g.


class Thing1 {
var $thing2s;

function Thing1()
{
$this->thing2s = array();
}

function getThing2($argument)
{
if (!array_key_exists($argument, $this->thing2s)) {
$this->things2[$argument] = new Thing2($argument);
}
return $this->things2[$argument];
}
}


Now I'm reasonably sure that the above is putting a Thing2 instance into the $things2 array, and returning a COPY. I want to return a reference. Which I would do with


return &$this->things2[$argument];


Right?

Source: http://community.livejournal.com/php/554973.html